I would love to know which of the three methods you prefer. So, now that you’ve gone through the basics, how about testing out your skills? Each level below has 5 questions. ![]() I’ll walk you through the 4 steps involved in this video: Basically, what you’ll do is set up a bunch of equations and then solve them to get the coefficients (numbers in front of the formula). The final method is for those who loves solving algebraic equations or when you’re trying to balance complex equations (like the ones in Ninja level – see practice questions below). There are 4 simple steps in balancing equation using this method. It pretty much works like the first method, however, you keep track of the changes by writing them down. We’ll try out the second method on this new equation. You can take my word for it, or give it a try and see how long it’ll take you to balance this equation by inspection. ![]() However, it gets taxing when you encounter more complicated equation like this: C 6H 5F + O 2 → CO + H 2O + F 2. This is a rather popular method and it works pretty well to a certain extent. Since we added a 2 in front of NaCl, our Na on the right-hand side is no longer balanced, so we’ll need to add a 2 in front of NaF as well. ![]() So, we’ll place a 2 in front of NaCl like this: Looks like it’s not balanced since there’s one on the left but two on the right. Na is balanced since there is one on the left-hand side and one on the right-hand side. You balance the equation by inspecting it. Personally, I prefer Method 2 when it comes to solving easy to intermediate equations because it is simple and doesn’t tax my brain too much. There are 3 methods in mastering this art. If you count the number of atoms on both sides, you’ll notice that they are not equal: The compounds on the left-hand side (before the arrow) are called reactants while the compounds on the right-hand side (after the arrow) are called products. So the main goal of balancing chemical equation is to get the number of atoms to be the same on each side of the equation. You’ll be able to get the molar ratios for all the compounds involved in the reaction and that will enable you to perform various types of calculations correctly (more on that in future posts). Jokes aside, being able to balance chemical equation will open up a lot of possibilities. View Notes.Is it important to be able to balance chemical equations correctly and quickly? You bet! Why so? First of all, you’ll make your chemistry teacher happy and maybe impress someone else along the way. Technical information, teaching suggestions, and related resources that complement this Concept Builder are provided on the Notes page. Learners and Instructors may also be interested in viewing the accompanying Notes page. However, the 18 different groups of questions can be printed. There is no need for an activity sheet for this Concept Builder. Looking at carbon, we see that there are seven atoms on the left and only one on the right. Users are encouraged to open the Concept Builder and explore. We can start balancing this equation by looking at either carbon or hydrogen.The built-in score-keeping makes this Concept Builder a perfect candidate for a classroom activity. Question-specific help is provided for each of the 18 situations. There are a total of 36 questions organized into 18 different Question Groups and spread across the three difficulty levels. Each difficulty level builds on the previous level. The Balancing Chemical Equations Concept Builder provides learners with experience balancing chemical equations by entering coefficients and conducting an atom count for each element on the reactant and the product side of the equation. ![]() Concept Builders » Chemistry » Balancing Chemical Equations
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